A very Very simple math problem

[vacitah]

sorry for all of the question's but exams are coming up and i have to start getting organized anyway can plz post the entire soloution it is a grade 11 uni math class

determine the coordinates of the points of intersection of each line and conic

x^2+y^2=2
x-2y+3=0

have fun
what is a good graphing calc for the comp the power toy in microsoft i can't get it to plot circles and put two graphs on top of each other any help in any area will greatly be apprecaited thx in advance now i have to get to the rest of the problems

[Mace]

Isolate x in the second equation and write it in terms of y. Plug is value into the first equation and solve for y (you should get a quadratic equation). Solve this equation for y - you should get two y values.

Now plug that y into equation 2 and solve for x. Those are your points of intersection.

[EchoAngel911]

x^2 + y^2 = 2 and x - 2y + 3 = 0

x = 2y - 3,
(2y-3)^2 + y^2 = 2,
4y^2 -12y +9 + y^2 = 2,
5y^2 - 12y + 7 = 0, could use quadratic equation, but ...
(5y - 7)(y - 1) = 0,

where y - 1 = 0 or 5y - 7 = 0,
y = 1 y = 7/5

get x value ( sub y values into x = 2y - 3)
x = -1 x= -1/5

[sonick]

nerds....








:D

[othy]

Jeez I hope all grade 11 students aren't like that..

:confused:

[jackc00]

Jeez I hope all grade 11 students aren't like that..

:confused:

lol.... totally agree...

[AnimeEd]

what the hell are conics?
circles?

[rafiki]

circles, ellipses, parabolas, and hyperbolas are all conics if my memory serves me right...

[mahjongmaniac]

AHHHHHHHHHHHH..... its too hard!!!!!!!!!...... :lol:




j/k... j/k....

that's some old math man... like ~>4 yrs ago for me....

[champ91]

it's like a bloody tutorial forum....
:lol:

[artsreview]

what the hell are conics?
circles?
The shapes you get when you slice a cone at various angles.

[bluetroll]

i could solve this but i did enough math today already....

[d_jedi]

x^2 + y^2 = 2 and x - 2y + 3 = 0

x = 2y - 3,
(2y-3)^2 + y^2 = 2,
4y^2 -12y +9 + y^2 = 2,
5y^2 - 12y + 7 = 0, could use quadratic equation, but ...
(5y - 7)(y - 1) = 0,

where y - 1 = 0 or 5y - 7 = 0,
y = 1 y = 7/5

get x value ( sub y values into x = 2y - 3)
x = -1 x= -1/5

Correct.
Just simple algebra :->

[Neb]

Wow, can't beeilve i dont' remmeber much from grd 11 math... I am alwaasy afraid one day if i have kids and they ask me math questinos adn I cant' help them :(

[grant]

That's ok Neb, RFD will always be around to do homework for your kids, no matter how stupid or lazy they may be!

[rafiki]

LOL

save money and get your hw done by other ppl ...ahh..rfd..

[isleepinadrawer]

maple owns you

[EchoAngel911]

it was a simple question

;)

[felix]

ah .. brings back memories :D

[zeroace]

After looking at double and triple integrals, I'm happy to say I can still solve that.